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46.Identify compound X in the following sequences of reactions :(1)(2)(3)(4)Sol.147.Identify a molecule which does not exist.(1) C2(2) O2(3) He2(4) Li23Diatomic molecule for which bond order is zero or negative does not exist.MoleculeBOC22O22He2ZeroLi21Sol.48.Sol.Which of the following is a natural polymer ?(1) polybutadiene(2) poly (Butadiene-acrylonitrile(3) cis-1,4-polyisoprene(4) poly (Butadiene-styrene)3

49.Sol.50.An increase in the concentration of the reactants of a reaction leads to change in :(1) threshold energy(2) collision frequency(3) activation energy(4) heat of reaction2Collision frequency, as number of molecules per unit volume increases.Anisole on cleavage with HI gives :(1)(2)(3)(4)Sol.351.The number of protons, neutrons and electrons inSol.(1) 71, 71 and 104(3) 71, 104 and 71317571 Lu, respectively, are :(2) 175, 104 and 71(4) 104, 71 and 71 n p 175Lu p 71 of protonsno. of neutronsno. of electrons 71175 – 71 10471The calculated spin only magnetic moment of Cr2 ion is :(1) 5.92 BM(2) 2.84 BM(3) 3.87 BM(4) 4.90 BM

Sol.4Cr2 1s2 2s2 2p6 3s2 3p6 3d4 4 unpaired electrons n n 2 4 4 2 4.8989 4.9 B.M.53.Match the ii)(iv)NatureBasicNeutralAcidicAmphotericWhich of the following is correct option cidic(i)(ii)(iii)(iv)(ii)(i)(iv)(iii)NeutralUrea reacts with water to form A which will decompose to form B. B when passed through Cu2 (aq), deep blue colour solution C is formed. What is the formula of C from the following ?(1) Cu(OH)2(3) CuSO44(2) CuCO3.Cu(OH)2(4) [Cu(NH3)4]2

55.Sol.56.Sol.57.Sol.58.Match the following and identify the correct option.(a)CO(g) H2(g)(i)Mg(HCO3)2 Ca(HCO3)2(b)Temporary hardness of water(ii)An electron deficient hydride(c)B2H6(iii)Synthesis gas(d)H2O2(iv)Non-planar )(ii)(iv)(3)(iii)(i)(ii)(iv)(4)(iii)(ii)(i)(iv)3 CO(g) H2(g) Water gas or synthesis gas Temporary hardness of water is due to bicarbonates of Ca2 & Mg2 B2H6 is a electron deficient compound due to presence of banana bond. H2O2 open book like structure which is non-planarThe mixture which shows positive deviation from Raoult’s law is :(1) Acetone Chloroform(2) Chloroethane Bromoethane(3) Ethanol Acetone(4) Benzene Toluene3Acetone ethanol shows positive deviation from Raoult’s law. Pure ethanol possesses H-bondingand adding acetone to ethanol causes breaking of some H-bonds.This causes increase in observed vapour pressure.The freezing point depression constant (Kf) of benzene is 5.12 K kg mol–1. The freezing pointdepression for the solution of molality 0.078 m containing a non-electrolyte solute in benzene is(rounded off upto two decimal places) :(1) 0.40 K(2) 0.60 K(3) 0.20 K(4) 0.80 K1 Tf ikfm T f 1 5.12 0.078 0.3993 0.40 KWhich of the following set of molecules will have zero dipole moment ?(1) Nitrogen trifluoride, beryllium difluoride, water, 1,3-dichlorobenzene(2) Boron trifluoride, beryllium difluoride, carbon dioxide, 1,4-dichlorobenzene(3) Ammonia, beryllium difluoride, water 1,4-dichlorobenzene(4) Boron trifluoride, hydrogen fluoride, carbon dioxide, 1,3-dichlorobenzene

Sol.2FFBNon-polar moleculeFF–Be–FO C ONon-polar moleculeNon-polar moleculeClNon-polar moleculeCl1,4-dichlorobenzene59.Sol.60.Sol.A tertiary butyl carbocation is more stable than a secondary butyl carbocation because of which ofthe following ?(1) –R effect of –CH3 groups(2) Hyperconjugation(3) –I effect of –CH3 groups(4) R effect of –CH3 groups2Find out the solubility of Ni(OH)2 in 0.1 M NaOH. Given that the ionic product of Ni(OH)2 is 2 10–15.(1) 1 10–13 M(2) 1 108 M(3) 2 10–13 M(4) 2 10–8 M3Ni(OH)2Ni2 2OH––s0.1 M Ksp [Ni2 ] [OH–]2 ksp s (0.1)22 10 15 s s 2 10–13 M0.12

61.Sol.Reaction between acetone and methylmagnesium chloride followed by hydrolysis will give:(1) Tert. butyl alcohol(2) Isobutyl alcohol(3) Isopropyl alcohol(4) Sec. butyl alcohol162.Which of the following amine will give the carbylamine test?N(CH3)2(1)Sol.NHC2H5(2)NH2(3)NHCH 3(4)3Carbyl amine reaction is give by 1 amine & anilene.63.An alkene on ozonolysis gives methanal as one of the product. Its structure is:CH2–CH CH2(1)Sol.1CH2CH 2CH 3(2)CH CH–CH 3(3)CH2–CH 2–CH 3(4)

64.Sol.A mixture of N2 and Ar gases in a cylinder contains 7 g of N2 and 8 g of Ar. If the total pressure ofthe mixture of the gases in the cylinder is 27 bar, the partial pressure of N2 is:[Use atomic masses (in g mol–1): N 14, Ar 40](1) 15 bar(2) 18 bar(3) 9 bar(4) 12 bar1According to Dalton’s lawPN2 N2 Ptotal 7 28 27 87 40 28 0.25 0.2 0.25 27 15 bar65.Which of the following is the correct order of increasing field strength of ligands to form coordination compounds ?(1) F– SCN– C2O2– CN–4(2) CN– C2O2– SCN– F–4(3) SCN– F– C2O2– CN–4(4) SCN– F– CN– C2O2–4Sol.3Fact from spectrochemical series66.Paper chromatography is an example of :(1) Thin layer chromatography(2) Column chromatography(3) Adsorption chromatography(4) Partition chromatography4It is an example of partition chromatography as mixture of substance are separated by partition.Sol.67.Sol.Sucrose on hydrolysis gives:(1) -D-Glucose -D-Fructose(3) -D-Glucose -D-Fructose1(2) -D-Fructose -D-Fructose(4) -D-Glucose -D-Glucose

68.Sol.The rate constant for a first order reaction is 4.606 10–3 s–1. The time required to reduce 2.0 g ofthe reactant to 0.2 g is:(1) 500 s(2) 1000 s(3) 100 s(4) 200 s11 Cot K ln Ct 12 2.303 log4.606 10 30.2 1log102 10 3 500 sec69.Sol.Reaction between benzaldehyde and acetophenone in presence of dilute NaOH is known as:(1) Cross Cannizzaro’s reaction(2) Cross Aldol condensation(3) Aldol condensation(4) Cannizzaro’s reaction2Two different carbonyl compound is treated with base known as crossed aldol condensation.70.Sol.Which of the following is not correct about carbon monoxide?(1) The carboxyhaemoglobin (haemoglobin bound to CO) is less stable than oxyhaemoglobin.(2) It is produced due to incomplete combustion.(3) It forms carboxyhaemoglobin.(4) It reduces oxygen carrying ability of blood.1CO when combine with haemoglobin it forms carboxyhaemoglobin which more stable thanoxyhaemoglobin thats why it reduces oxygen carring ability of blood.

71.Sol.72.Sol.73.Hydrolysis of sucrose is given bythe following reactionSucrose H2OGlucose FructoseIf the equilibrium constant (Kc) is 2 1013 at 300 K, the value of rGº at the same temperature willbe:(1) 8.314 J mol–1 K–1 300 K ln(3 1013)(2) –8.314 J mol–1 K–1 300 K ln(4 1013)(3) –8.314 J mol–1 K–1 300 K ln(2 1013)(4) 8.314 J mol–1 K–1 300 K ln(2 1013)3 G –RT ln K G – 8.314 300 ln (2 1013)HCl was passed through a solution of CaCl2, MgCl2 and NaCl. Which of the following compounds(s)crystallise(s)?(1) only MgCl2(2) NaCl, MgCl2 and CaCl2(3) Both MgCl2 and CaCl2(4) Only NaCl1MgCl2 has least solubility among CaCl2, MgCl2 & NaCl thats why it crystallise first on passing HCl.An element has a body centered cubic (bcc) structure with a cell edge of 288 pm. The atomicradius is:(1)Sol.43 288 pm(2)42 288 pm(3)3 288 pm4(4)2 288 pm43For bcc3 a 4r3 288 pm4 r 74.Sol.Which of the following oxoacid of sulphur has –O–O– linkage?(1) H2S2O8, peroxodisulphuric acid(2) H2S2O7, pyrosulphuric acid(3) H2SO3, sulphurous acid(4) H2SO4, sulphuric acid1OOSHOOOOHSOO(H2S2O8)

OOSHOSOOOH(H2S2O7)OOS(H 2SO3)HOOHOSHOO(H 2SO4)OH75.Identify the incorrect statement.(1) Interstitial compounds are those that are formed when small atoms like H, C or N are trappedinside the crystal lattices of metals(2) The oxidation states of chromium in CrO24 and Cr2O72 are not the sameSol.76.Sol.(3) Cr2 (d4) is a stronger reducing agent than Fe2 (d6) in water(4) The transition metals and their compounds are known for their catalytic activity due to theirability to adopt multiple oxidation states and to form complexes2(1) Interstitial compounds are those compounds that are formed when small atoms like H, B, C or Nare trapped inside crystal lattices of metals.(2) Oxidation state of chromium in CrO42– & Cr2O72– are 6 (same)(3) FactCr2 is stronger reducing agent than Fe2 in water on the basis of standard reduction potential.(4) Transition metals are one of the best available catalyst due to their ability to adopt multipleoxidation states & to form complexes.Which of the following is a cationic detergent?(1) Cetyltrimethyl ammonium bromide(2) Sodium dodecylbenzene sulphonate(3) Sodium lauryl sulphate(4) Sodium stearate1Cetyltrimethyl ammonium bromide is a cationic detergent as it hydrophillic part is a quateinaryammonium ion.

77.Sol.78.Sol.79.Sol.80.Sol.The correct option for free expansion of an ideal gas under adiabatic condition is:(1) q 0, T 0 and w 0(2) q 0, T 0 and w 0(3) q 0, T 0 and w 0(4) q 0, T 0 and w 03For an adiabatic process, q 0for free expansion, Pext 0 w 0& from First law of Thermodynamics, E 0or T 0On electrolysis of dil. sulphuric acid using platinum (Pt) electrode, the product obtained at anodewill be:(1) H2S gas(2) SO2 gas(3) Hydrogen gas(4) Oxygen gas4Anode : 2H2O O2 4H 4e–Cathode : 2H 2e– H2(g) oxygn gas will be obtained at anode.Identify the correct statement from the following:(1) Vapour phase refining is carried out for Nickel by Van Arkel method(2) Pig iron can be moulded into a variety of shapes(3) Wrought iron is impure iron with 4% carbon(4) Blister copper has blistered appearance due to evolution of CO22(1) Vapour phase refining is carried out for nickel by Mond process.(2) Pig iron is molten iron obtained from blast furnace after smelting it can be moulded into varietyof shapes.(3) Wrought iron is the purest form of iron which has less than 4% carbon.(4) Blister copper has blistered appearance due to evolution of SO2.Which of the following is a basic amino acid?(1) Tyrosine(2) Lysine(3) Serine2(Lysine)Basic part is more than acidic part so lysine is basic amino acid.(4) Alanine

81.Sol.82.Sol.83.Sol.Identify the incorrect match.NameIUPAC Official Name(a) Unnilunium(i) Mendelvium(b) Unniltrium(ii) Lawrencium(c) Unnilhexium(iii) Seaborgium(d) Unununnium(iv) Darmstadtium(1) (c), (iii)(2) (d), (iv)(3) (a), (i)2101 - Unnilunium - Mendelevium103 - Unniltrium - Lawrencium106 - Unnilhexium - Seaborgium111 - Unununium - RoentgeniumWhich of the following alkane cannot be made in good yield by Wurtz reaction?(1) n-Heptane(2) n-Butane(3) n-Hexane(4) 2,3,-Dimethylbutane1Wurtz reaction is used to prepare symmetrical alkane.Elimination reaction of 2-Bromo-pentane to form pent-2-ene is:(a) -Elimination reaction(b) Follows Zaitsev rule(c) Dehydrohalogenation reaction(d) Dehydration reaction(1) (b), (c), (d)(2) (a), (b), (d)(3) (a), (b), (c)(4) (a), (c), (d)3In the reaction84.Sol.(4) (b), (ii)(i)(ii)(iii)Dehydrohalogenation - elimination reactionfollows zaitsev rule (highly substituted alkene is formed as major product)The number of Faradays (F) required to produce 20g of calcium from molten CaCl2 (Atomic mass ofCa 40 g mol–1) is:(1) 3(2) 4(3) 1(4) 23EquivalentCa Equivalentcurrent W nf No. of FaradaysMM No. of Faradays 20 240 No. of Faradays 1

85.Sol.86.Sol.87.Sol.Which one of the followings has maximum number of atoms?(1) 1g of O2(g) (Atomic mass of O 16)(2) 1g of Li(s) (Atomic mass of Li 7)(3) 1g of Ag(s) (Atomic mass of Ag 108)(4) 1g of Mg(s) (Atomic mass of Mg 24)2(1) no. of atoms 1 NA7(2) no. of atoms 1 NA108(3) no. of atoms 1 NA24(4) no. of atoms 1 2 NA32 1 gm of Li is having maximum no. of atoms.For the reaction, 2Cl(g) Cl2(g), the correct option is:(1) rH 0 and rS 0(2) rH 0 and rS 0(3) rH 0 and rS 0(4) rH 0 and rS 022Cl(g) Cl2(g) HeatDue to bond formation stability increases which results in release of heat. Hr –ve or exothermic process Hr O& S O, because number of Cl atoms decreases in the formation of Cl2(g)Identify the correct statements from the following:(a) CO2(g) is used as refrigerant for ice cream and frozen food(b) The structure of C60 contains twelve six carbon rings and twenty five carbon rings.(c) ZSM-5, a type of zeolite, is used to convert alcohols into gasoline(d) CO is colourless and odourless gas(1) (b) and (c) only(2) (c) and (d) only(3) (a), (b) and (c) only(4) (a) and (c) only2 CO2 (s) is used as refrigerant for ice cream & frozen food.six carbon rings – 20C60 five carbon rings – 12 ZSM-5 zeolite used to convert alcohols into gasoline CO is colourless & odourless gas

88.Sol.89.Sol.90.Sol.Measuring Zeta potential useful in determining which property of colloidal solution?(1) Stability of the colloidal particles(2) Size of the colloidal particles(3) Viscosity(4) Solubility1A large ve or –ve value of Zeta potential indicate good stabilityWhat is the change in oxidation number of carbon in the following reaction?CH4(g) 4Cl2(g) CCl4(l) 4HCl(g)(1) –4 to 4(2) 0 to –4(3) 4 to 4(4) 0 to 41The following metal ion activates many enzymes, participates in the oxidation of glucose toproduce ATP and with Na, is responsible for the transmission of nerve signals.(1) Calcium(2) Protassium(3) Iron(4) Copper2Potassium